Valid Parenthesis
Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
An input string is valid if:
- Open brackets must be closed by the same type of brackets.
- Open brackets must be closed in the correct order.
Example 1:
Input: s = "()" Output: true
Example 2:
Input: s = "()[]{}"
Output: true
Example 3:
Input: s = "(]" Output: false
Constraints:
1 <= s.length <= 104sconsists of parentheses only'()[]{}'.
Solution 1: Using Stack
- Push if it’s an opening bracket and if it’s a closing bracket pop and check if it’s the same.
- Check if stack if empty is a valid string.
public boolean isValid(String s) {
Stack<Character> stack = new Stack<Character>();
for (char c : s.toCharArray()) {
if (c == '(')
stack.push(')');
else if (c == '{')
stack.push('}');
else if (c == '[')
stack.push(']');
else if (stack.isEmpty() || stack.pop() != c)
return false;
}
return stack.isEmpty();
}